Silver crystallizes in fcc lattic. If the edge length of the cell is `4.07 xx 10^(-8) cm` and density is `10.5 g cm^(-3)`. Calculate the atomic mass of silver.

Explanation

No. of silver atoms =1 million `=1xx10^6`
Mass of one million Ag atoms `=1.79xx10^(-16) g`.
Mass of `6.023xx10^23` atoms of silver `=(1.79xx10^-16 g)/(1xx10^6)xx6.023xx10^23`
`=107.8 g`.
Atomic mass of silver `=6.023 xx10^23` atoms of Ag
`therefore` The atomic mass of `Ag=107.8 g`.