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The quantun mechanical treatment of the ...

The quantun mechanical treatment of the hydrogen atom gives the enrgy value:
`E_(n) = (-13.6)/(n^2) eV "atom"^(-1)`.
Calculate the wavelength corresponding to the above transition.

Text Solution

Verified by Experts

Wave length = `lambda`
`Delta E = (hc)/(lambda)`
`Delta E = 0.661 xx 1.6 xx 1.6 xx 10^(-19) J`
`= 1.06 xx 10^(-19)J`
h = Plank.s constant `= 6.626 xx 10^(-34) Js^(-1)`
`c = 3 xx 10^(8) m//s`
`:. lambda = (6.626 xx 10^(-34) JS xx 3 xx 10^8 ms^(-1))/(1.06 xx 10^(-19) J)`
`lambda = 1.875 xx 10^(6) m`.
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