What is the de Broglie wavelength (in cm) of a 160g cricket ball travelling at `140 Km hr^(-1)`.

Explanation

m = mass of the cricket ball `= 160 g = 0.16 kg`
v = velocity of the cricket ball = `140 km hr^(-1)`
`=(140 xx 10^3)/(60 xx 60) ms^(-1) = 38.88 ms^(-1)`
h = Plank.s constant = `6.626 xx 10^(-34) Kg m^2 s^(-1)`
de broglie equation = `(6.626 xx 10^(-34) xx cancel(Kg) cancel(m^2)cancel(s^(-1)))/(0.16 cancel(Kg) xx 38.88 cancel(ms^(-1)))`
`lambda = (6.626 xx 10^(-34))/(6.2208)`
Wave length in cm = `1.065 xx 10^(-34) xx 100`
`=1.065 xx 10^(-32) cm` (or)
`1.065 xx 10^(-34) m`.