Home
Class 11
CHEMISTRY
The de-Broglie wavelength of a particle ...

The de-Broglie wavelength of a particle with mass 1 g and velocity `100 m//s` is

A

`6.63 xx 10^(-35) m`

B

`6.63 xx 10^(-34) m`

C

`6.63 xx 10^(-33) m`

D

`6.65 xx 10^(-35) m`

Text Solution

Verified by Experts

The correct Answer is:
C
`lambda = h/(mv) = (6.63 xx 10^(-34))/(1 xx 10^(-3) xx 100) = 6.63 xx 10^(-33) m`
Promotional Banner

Topper's Solved these Questions

  • QUANTUM MECHANICAL MODEL OF ATOM

    SURA PUBLICATION|Exercise ADDITIONAL SHORT ANSWER|39 Videos

  • QUANTUM MECHANICAL MODEL OF ATOM

    SURA PUBLICATION|Exercise ADDITIONAL LONG ANSWER|20 Videos

  • QUANTUM MECHANICAL MODEL OF ATOM

    SURA PUBLICATION|Exercise NUMERICAL|4 Videos

  • PUBLIC EXAMINATION - MARCH 2019

    SURA PUBLICATION|Exercise Part - IV|19 Videos

  • SOLUTIONS

    SURA PUBLICATION|Exercise NUMERICAL PROBLEMS|24 Videos

Similar Questions

Explore conceptually related problems

The de Broglie wave corresponding to a particle of mass m and velocity upsilon has a wavelength associated with it

The de-Broglie wavelength of a tennis ball of mass 60g moving with a velocity of 10 ms^(-1) is approximately (planck's constant, h = 6.63 xx 10^(-34) Js)

The de Broglie wavelength and kinetic energy of a particle is 2000 Å and 1 eV respectively. If its kinetic energy becomes 1 MeV, then its de Broglie wavelength is

A particle is moving three times as fast as an electron. The ratio of the de Broglie wavelength of the particle to that of the electron is 1.813xx10^(-4) . Calculate the particle's mass and identify the particle.

Calculate the De-Broglie wavelength of a particle whose momentum is 66.26 xx 10^(-28) kg ms^(-1) .

Find the de-Broglie wavelength of an electron moving with a speed of 5.2 xx 10^(5) m//s

The de- Broglie wavelength of a particle of kinetic energy K is lambda what would be the wavelength of the particle, if its kinetic energy were K/4 ?

What is the de Broglie wavelength of a. a bullet of mass 0.040 kg travelling at the speed of 1.0 km/s, b. a ball of mass 0.060 kg moving at a speed of 1.0 m/s, and c. a dust particle of mass 1.0xx10^(-9) kg drifting with a speed of 2.2 m/s ?

SURA PUBLICATION-QUANTUM MECHANICAL MODEL OF ATOM-ADDITIONAL QUESTIONS - CHOOSE THE CORRECT ANSWER
  1. Maximum number of electrons in a subshell of an atom is determined by ...

    Text Solution

    |

  2. Who modified Bohr's theory by introducing elliptical orbits for electr...

    Text Solution

    |

  3. The de-Broglie wavelength of a particle with mass 1 g and velocity 100...

    Text Solution

    |

  4. The number of nodes in s orbital of any energy level is equal to

    Text Solution

    |

  5. Which of the following is not among short comings of Bohr's model?

    Text Solution

    |

  6. Assertion (A) : Energy of an electron is taken negative. Reason (R )...

    Text Solution

    |

  7. What will be the wavelength of a ball of mass 0.1 kg moving with a vel...

    Text Solution

    |

  8. Assertion (A) : Bohr's orbits are also called stationary states. Rea...

    Text Solution

    |

  9. The wavelengrh associated with an electron moving with velocity 10^(10...

    Text Solution

    |

  10. Assertion (A) : Angular momentum of an electron in an atom is quantize...

    Text Solution

    |

  11. Assertion (A) : The orbitals having equal energy are known as degenera...

    Text Solution

    |

  12. The de-Broglie wavelength associated with a matter particle is

    Text Solution

    |

  13. The electronic configuration of copper is .

    Text Solution

    |

  14. How many nodes are possible for 2z orbtial?

    Text Solution

    |

  15. The subsidiary quantum number decides .

    Text Solution

    |

  16. Consider the following statements and pick the incorrect statement(s)....

    Text Solution

    |

  17. As per Aufbau principle, arrange the orbitals in increasing order of e...

    Text Solution

    |

  18. In multi-electron atom, 4s - orbital is lower in energy than

    Text Solution

    |

  19. Shape of an orbital is given by

    Text Solution

    |

  20. Orientation of orbitals is given by

    Text Solution

    |