The uncertainty in the position and velocity of a particle are `10^(-2)m and 5.27 xx 10^(-24) ms^(-1)` respectively. Calculate the mass of the particle.
Given : `h = 6.626 xx 10^(-34) kg m^2s^(-1)`
`Deltav = 5.27 xx 10^(-24) ms^(-1) , Deltax = 10^(-2) m`

Explanation

Mass of the particle
`m = h/(4 pi Deltax Deltav) kg`
`= (6.626 xx 10^(-34) kg m^2 s^(-1))/(4 xx 3.143 xx 10^(-2)m xx 5.27 xx 10^(-24) ms^(-1))`
`= 1 xx 10^(-9) kg`
`m = 1 xx 10^(-9) kg`.