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The emf of the following cell at 25^(@)C...

The emf of the following cell at `25^(@)C` is equal to 0.34 V. Calculate the reduction potential of copper electrode.
`Pt(s)abs(H_(2)(g,1atm)|H^(+)(aq, 1M))abs(Cu^(2+)(aq, 1M))Cu(s)`

Text Solution

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`E_("Cell")^(@)=0.34V`
`E_("Cell")^(@)=E_("anode"^(@)+E_("Cathode")^(@)`
`" "=(E_("ox")^(@))_(SHE)+(E_("red")^(@))_(Cu^(2+)|Cu)`
`0.34=0+(E_("red")^(@))_(Cu^(2+)|Cu)`
`therefore E_(Cu^(2+)|Cu)^(@)=0.34V`.
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