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The emf of the cell Cd//CdCl(2)," "25H(2...

The emf of the cell `Cd//CdCl_(2)," "25H_(2)O" "//AgCl_((s))Ag` is 0.675 V. Calculate of the cell reaction.

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Given : Cell reaction is,
`Cd//CdCl_(2)," "25H_(2)O" / "AgCl_((s))AgE^(@)=0.675V`
`Cd rarr Cd^(2+)+2e^(-)`
n = 2
F = 96495 coulombs
Formula : `Delta G = -nFE`
Solution : `DeltaG=-2 times 96495 times 0.675`
`Delta G=-130.26 kJ`
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