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The standard free energy change of the r...

The standard free energy change of the reaction `M^(+)""_((aq))+e^(-) rarr M_((s))` is -23.125 kJ. Calculate the standard emf of the half cell.

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Given :
`DeltaG=-23.125 kJ=-23.125 times 103 J`
`F=96945` coulombs
`thereforen=1`
Formula : `DeltaG^(@)=-nFE^(@)`
`thereforeE^(@)=-(DeltaG)/(nF)`
Solution : `" "=-((-23.125 times 10^(3))/(1 times 96495))`
`" "=(23.125 times 10^(3))/96495`
`" "=0.239`
`E^(@)=+0.239V`
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