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The emf of the half cell Cu^(2+)""((aq))...

The emf of the half cell `Cu^(2+)""_((aq))//Cu_((s))` containing 0.01 M `Cu^(2+)` solution is +0.301 V. Calculate the standard emf of the half cell.

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Given : E = 0.301 V, `[Cu^(2+)]=0.01 M`
Formula :
`E^(@)""_(Cu^(2+)//Cu)=E_(Cu^(2+)//Cu)+(2.303RT)/(nF)log""([Cu^(2+)])/([Cu])`
Solution :
`" "=+0.301+0.0591/2log""0.01/1`
`E^(@)=0.301+0.059/2 times 2=0.3591V`
`E^(@)=0.36V`
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