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Calculate the emf of the cell Zn//ZnO(2)...

Calculate the emf of the cell `Zn//ZnO_(2), OH^(-)""_(aq),-HgO""//Hg` given that `E^(@)` values of `OH^(-), ZnO` and `OH^(-), HgO""//Hg` half cells are -1.216 V and 0.098 V respectively.

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Given :
`Zn//ZnO_(2)^(-), OH^(-)""_((aq)), HgO""//Hg`
`" "E^(@)""_(R)=0.098V, E_(L)=-1.216V`
Formula : `therefore E^(@)""_(cell)=E^(@)""_(R)-E^(@)""_(L)`
Solution : `E^(@)""_(cell)=0.098-(-1.216)`
`" "=0.098+1.216=+1.314`
`E^(@)=+1.314V`.
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