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A transistor having abeta equal to 80 ha...

A transistor having `abeta` equal to 80 has a change in base current of `250muA`, then the change in collector current is

A

20,000 mA

B

200 mA

C

2000 mA

D

20 mA

Text Solution

Verified by Experts

The correct Answer is:
D

`beta = Deltai_(c)/Deltai_(b)`
`implies 80 = Delta i_(c)/(250 xx 10^(-6))`
`implies Delta i_(c) = 80 xx 250 xx 10^(-6) = 20 xx 10^(-3) = 20mA`
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