A common emitter transistor amplifier has a current gain of 50. If the load resistance is `4 kOmega` and input resistance is `500 Omega`, the voltage gain of the amplifier is

Options

A. 100
B. 200
C. 300
D. 400

Answer

D

Explanation

Given that, For a CE transistor amplifier,
Current gain, `beta = 50`
Load resistance, `R_(L) = 4 K Omega = 4000 Omega`
Input resistance, `R_(i) = 500 Omega`
Voltage gain, `A_(V) = ?`
`A_(V) = beta(R_(L)/R_(i)) = 50(4000/500) = 400`
`:. A_(V) = 400 V`