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A steel wire of length 20 cm is stretche...

A steel wire of length 20 cm is stretched to increase its length by 0.2 cm. Find the lateral strain in the wire if the Poissin's ratio for steel is 0.19.

Text Solution

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Length of wire, `l=20,cm=0.20m,`
`"Poisson.s ratio,"sigma=0.19`
Increase in length,`Deltal=0.2cm=2xx10^(-3)m`
lateral strain=?
`"Lateral strain"=sigmaxx"longitudinal strain .e."`
`"But e"=(Deltal)/(l)`
`therefore"Lateral strain"=sigma(Deltal)/(l)=(0.19xx2xx10^(-3))/(0.20)`
`=1.9xx10^(-3)=0.0019m.`
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