Assertion: Glucose reacts with hydroxylamine to form an oxime and alsoadds a molecule of hydrogen cyanide to give cyanohydrin. Reason: The carbonyl group is present in the open chain structure of glucose.
A
Both assertion and reason are correct statements, and reason is the correct explanation of the assertion
B
Both assertion and reason are correct statements, but reason is not the correct explanation of the assertion
C
Assertion is correct, but reason is wrong statement.
D
Assertion is wrong, but reason is correct statement.
Text Solution
AI Generated Solution
The correct Answer is:
To solve the question, we need to analyze both the assertion and the reason provided.
### Step 1: Understanding the Assertion
The assertion states that glucose reacts with hydroxylamine to form an oxime and also adds a molecule of hydrogen cyanide to give cyanohydrin.
1. **Structure of Glucose**: Glucose is an aldehyde (specifically, an aldohexose) with the structure C6H12O6. In its open-chain form, it has a carbonyl group (C=O) at one end (the aldehyde group).
2. **Reaction with Hydroxylamine**: Hydroxylamine (NH2OH) reacts with the carbonyl group of glucose. The reaction involves the nucleophilic attack of the nitrogen atom on the carbonyl carbon, followed by the elimination of water (H2O), leading to the formation of an oxime.
3. **Reaction with Hydrogen Cyanide**: Similarly, glucose can react with hydrogen cyanide (HCN). The carbonyl group again acts as a site for nucleophilic attack by the cyanide ion (CN-), resulting in the formation of a cyanohydrin.
### Conclusion for Assertion
Thus, the assertion is correct: glucose does react with hydroxylamine to form an oxime and with HCN to form a cyanohydrin.
### Step 2: Understanding the Reason
The reason states that the carbonyl group is present in the open-chain structure of glucose.
1. **Carbonyl Group**: The carbonyl group (C=O) is indeed present in the open-chain structure of glucose, specifically as part of the aldehyde functional group.
2. **Importance of Carbonyl Group**: The presence of the carbonyl group is crucial for both reactions mentioned in the assertion, as it is the site of nucleophilic attack for both hydroxylamine and hydrogen cyanide.
### Conclusion for Reason
Therefore, the reason is also correct: the carbonyl group is present in the open-chain structure of glucose.
### Final Conclusion
Both the assertion and the reason are true, and the reason correctly explains the assertion.
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