Calculate the energy of the reaction ,
`Li^(7) + p to 2 _(2)He^(4)`
If the binding energy per nucleon in `Li^(7)` and `He^(4)` nuclei are 5.60 MeV and 7.06 MeV , respectively .

Find the energy of the reaction Li^(7)+prarr2He^(4) if the binding energies per nucleon in Li^(7) and He^(4) nuclei are known to be equal to 5.60 and 7.06 MeV respectively.

The energy of the reaction Li^(7)+prarr2He^(4) is ( the binding energy per nucleon in Li^(7) and He^(4) nuclei are 5.60 and 7.60 MeV respectively.)

The energy of the reaction Li^(7)+prarr2He^(4) is ( the binding energy per nucleon in Li^(7) and He^(4) nuclei are 5.60 and 7.60 MeV respectively.)

If the binding energy per nucleon in L i^7 and He^4 nuclei are respectively 5.60 MeV and 7.06 MeV . Then energy of reaction L i^7 + p rarr 2_2 He^4 is.

True or False Statements : In the nuclear reaction X^(200) rarr A ^(110)+B^(90) . If the binding energy per nucleon for X, A and B is 7.4 MeV, 8.2.MeV and 8.2 MeV respectively, the energy released is 160 MeV.

The mass defect of ""_(2)^(4)He is 0.03 u. The binding energy per nucleon of helium (in MeV) is

The binding energy per nucleon of _2He^4 is 7.075 MeV. What is its total binding energy?

Consider the nuclear fission Ne^(20) rarr 2He + C^(12) .The binding energy per nucleon are 8.03 MeV, 7.07 MeV and 7.86 MeV respectively. identify the correct statement

The mass defect of He_(2)^(4) He is 0.03 u. The binding energy per nucleon of helium (in MeV) is