Solve the following system of equations : `(21)/(x)+(47)/(y) = 110` `(47)/(x) =(21)/(y) = 162, x, y ne 0`
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Let `(1)/(x) = a and (1)/(y) = b` ` rArr 21a + 47b = 110 and 47a + 21b =162` Adding and subtracting the two equations, weget a+ b = 4 and a-b = 2 Solving the above two equations, we get a= 3 and b = 1 `therefore x = (1)/(3) and y = 1`
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