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Sides of a right triangular field are 25...

Sides of a right triangular field are 25m, 24m and 7m. At the three corners of the field, a cow, a buffalo and a horse are tied separately with ropes of 3.5 m each to graze in the field. Find the area of the field that cannot be grazed by these animals.

Text Solution

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Required Area = Area of triangle – Area of 3 sectors
Area of Triangle `= (1)/(2)xx 24 x 7= 84m^(2)`
Area of three sectors `=(pir^(2))/(360^(@))xx `(sum of three angles of triangle )
`= (22xx 7 xx 180^(@))/(7 xx 2xx2xx 360^(@)) = (77)/(4)` or `19.25 m^(2)`
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