A train covers a distance of 360 km at a uniform speed. Had the speed been 5km/hour more, it would have taken 48 minutes less for the journey. Find the original speed of the train

Explanation

Let the original speed of the train be x km/h
`therefore (360)/(x) - (360)/(x+5) = (48)/(60)`
`rArr x^(2) + 5 x - 2250 =0`
`rArr (x+ 50) 9x-45) =0 therefore x = 45`
Hence original speed of the train = 45km/h