The resistance of metal is given by `V = IR`, The voltage in the resistance is `V = (8 pm 0.5)V` and current in the resistance is `I = (2 +- 0.2)A`, the value fo resistance with its percentage error is

The resistance of a metal is given by R = V//I , where V is potential difference and I is current . In a circuit , the potential difference across resistance is V = ( 8 +- 0.5) V and current in resistance , I = ( 4 +- 0.2)A . What is the value of resistance with its percentage error?

The resistance of a metal is given by R = V//I , where V is potential difference and I is current . In a circuit , the potential difference across resistance is V = ( 8 +- 0.5) V and current in resistance , I = ( 4 +- 0.2)A . What is the value of resistance with its percentage error?

In a circuit potential difference across resistence V = (4 +- 0.25)V and curent in resistence , f = (1 +- 0.1) what is the value of resistence with its percentage error

The resistance of a metal is given by R=(V)/(I), where V is potential difference and I is the current. In a circuit the potential difference across resistance is V=(8+-0*5) V and current in resistance, I=(4+-0*2)A . And current in resistance with its percentage error :

Give, potential difference V = (8 + 0.5) V and current I = (2 + 0.2) A. The value of resistance R is

Give, potential difference V = (8 + 0.5) V and current I = (2 + 0.2) A. The value of resistance R is

The voltage measured across resistance is V = (50 pm 0.1)V and current is I = ( 10 pm 0.2) . Find error in resistance

the resistance R = V / I ,if V= (50+-2) and I=(5+- 0.1) ,find the percentage error in R.