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Largest real value for x such that `sum_(k=0)^(4) ((3^(4-k))/((4-k)!))((x^(k))/(k!))= 32/3`

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The correct Answer is:
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`underset(k=0)overset(4)sum((3^(4-k))/((4-k)!))((x^(k))/(k!))`
`=underset(k=0)overset(4)sum((4!)/((4-k)!k!)3^(4-k).x^(4).(1)/(4!))`
`= underset(k=0)overset(4)sum(.^(4)C_(k).3^(4-k).x^(4))/(04!)`
`= ((3+x)^(4))/(4!)`
According to the question ,
`((3+x)^(4))/(4!) = 32/3`
or `(3+x)^(4) = 256`
or `x + 3 = 256`
or `x = 1`
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