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A bag contains 5 white and 3 black balls...

A bag contains 5 white and 3 black balls. Four balls are successively drawn out without replacement. What is the probability that they are alternately of different colours?

Text Solution

Verified by Experts

The correct Answer is:
`1/7`
Required probability
`=P(WBWB)+P(BWBW)`
`=P(W)P(B//W)P(W//WB)P(B//BWB)`
`=5/8xx3/7xx4/6xx2/5+3/8xx5/7xx2/6xx4/5`
`=(1)/(14)+(1)/(14)=1/7`
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