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A die is thrown 4 times. Find the probab...

A die is thrown 4 times. Find the probability of getting at most two 6.

Text Solution

Verified by Experts

The correct Answer is:
`0.984`
Given that p =1/6,q=5/6. Therefore required probability is
`P(0)+P(1)+P(2)=""^(4)C_(0)((5)/(6))^(4)+""^(4)C_(1)((5)/(6))1/6+""^(4)C_(2)((5)/(6))^(2)((1)/(6))^(2)`
`=425/432=0.984`
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