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Let Aa n dB are events of an experiment ...

Let `Aa n dB` are events of an experiment and `P(A)=1//4, P(AuuB)=1//2,` then value of `P(B//A^c)` is `2//3` b. `1//3` c. `5//6` d. `1//2`

A

`2//3`

B

`1//3`

C

`5//6`

D

`1//2`

Text Solution

Verified by Experts

The correct Answer is:
B

`P(A)=1/4,P(AuuB)=1/2`
`P((B)/(A^(C)))=(P(Bnna^(C)))/(P(A^(C)))`
`=(P(AuuB)-P(A))/(1-P(A))`
`" "[becauseP(AuuB)+P(B)-P(AnnB)]`
`(1/2-1/4)/(1-1/4)=1/4xx4/3=1/3`
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