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A pair of fair dice is thrown independently three times. The probability of getting a score of exactly 9 twice is (1) 1/729 (2) 8/9 (3) 8/729 (4) 8/243

A

`8//9`

B

`7//29`

C

`8//243`

D

`1//729`

Text Solution

Verified by Experts

The correct Answer is:
C

Possiblities of getting 9 are `(5,4),(4,5),(6,43),(3,6).`
`thereforep=(4)/(36)=1/9andq=1-1/9=8/9`
Therefore, the required probability is
`""^(3)C_(2)q^(1)p^(2)=(3)((8)/(9))((1)/(9))^(2)=(8)/(143)`
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CENGAGE-PROBABILITY II-Exercise (Single)
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