The side AB of a parallelogram ABCD is produced to any point P. A line through A and parallel to CP meets CB produced at Q and then parallelogram PBQR is completed. Show that `a r\ (A B C D)\ =\ a r\ (P B Q R)dot`

Explanation

`ΔACQ` and `ΔAQP` are lying on the same base AQ and exist between the same parallels AQ and CP.


Two triangles on the same base (or equal bases) and between the same parallels are equal in area.


`Area (ΔACQ) = Area (ΔAPQ)`


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