If `OA = veca; OB = vecb; OC = 2a+3b, OD = a -2b`, the length of `OA` is three times the length of `OB` and `OA` is perpendicular to `DB`, then `(BD xx AC) . (OD xx OC)` is

In the figure OA=sqrt(80) , OB=8, OC=sqrt(20) . What is the length of OD?

O is any point inside the rectangle ABCD. If OB = 6cm, OD = 8cm and OA = 5cm, then find the length of OC.

In the given figure, Oa = OB and OC = OD. Which is the criteria to prove DeltaAOC ~=DeltaBOD .

An object is placed at A(OA gt f) . Here, f is the focal length of the lens. The image is formed at B. A perpendicular is erected at O and C is chosen such that /_BCA = 90^(@) . Let OA = a, OB = b and OC = c. Then the value of f is

An object is placed at A(OA gt f) . Here, f is the focal length of the lens. The image is formed at B. A perpendicular is erected at O and C is chosen such that /_BCA = 90^(@) . Let OA = a, OB = b and OC = c. Then the value of f is

In a triangle OAC, if B is the mid point of side AC and vec(OA)=veca,vec(OB)=vecb , then what is vec(OC) .

In quadrilateral ABCD, the diagonals AC and BD intersect each other at point O. If AO = 2CO and BO = 2DO, show that: OA xx OD = OB xx OC .