[" Factorixe "],[Q*a(a+b-c)-bc]

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bc- b -c-b- ccb

ab(a-b)+bc(b-c)+ca(c-a) is equal to : ab(a-b)+bc(b-c)+ca(c-a) किसके बराबर है ?

Prove that: 1/(bc+ca+ab)|[a, b, c],[a^2, b^2, c^2], [bc, ca, ab]|=(b-c),(c-a),(a-b)

Prove that : |{:(a,b,c),(a^(2),b^(2),c^(2)),(bc,ca,ab):}|=(a-b)(b-c)(c-a)(ab+bc+ca)

Prove that the following. [[a,b,c],[a^2,b^2,c^2],[bc,ca,ab]] =(b-c)(c-a)(a-b)(bc+ca+ab)

Prove that abs((a,b,c),(a^2,b^2,c^2),(bc,ca,ab))=(a-b)(b-c)(c-a)(ab+bc+ca)

If a :b::3:4 & b:c:: 4:7. then (a +b + c)/( c ) = ?

- aa bc a - b - c - - bb - c - c

If (a-2b-3c+4d)(a+2b+3c+4d) = (a+2b-3c-4d)(a-2b+3c-4d) then 2ad = "(a) 3bc (b) bc (c) 5bc (d) 2bc"