In the previous question, if the direction of `I` is reversed, `V_(B)-V_(A)` will be

In the previous question, (i) the force on T is proportional to i (ii) the force T is proportional to i^(2) (iii) if direction of I is reversed in the circuit be reversing E , the force on T will remain in the same direction

(A) Calculate the value of V_(0) and i if the silicon and germanium diode start conducting at 0.7 V and 0.3 V respectively. (B) If the Ge diode connection is now reversed, what will be the new values of V_(0) and i ?

Calculate the value of output voltage V_(0) and I if the Si diode and the Ge diode conduct at 0.7 V and 0.3V respectively, in the circuit given in Fig. If now Ge diode connections are reversed, what will be the new values of V_(0) and I.

Potential difference across AB , i.e., V_(A)-V_(B) is

If the above question, the potential has correct relations as given= A. V_(A) gt V_(B) gt V_(C) gt V_(D) B. V_(A) gt V_(B) ge V_(C) gt V_(D) C. V_(D)=V_(C)=V_(B)=V_(A) D. V_(C) lt V_(B) gt V_(A) gt V_(D)

In the circuit shown in the figure, the input voltage V_(i) is 20V, V_(BE)=0 and V_(CE) = 0 . The values of I_(B) , I_(C) and beta are given by

In the circuit shown in the figure, the input voltage V_i is 20 V, V_(BE) = 0 and V_(CE) = 0 . The values of I_B , I_C and beta are given by