If `(5)/(y-6) lt 0` where `y ne 6`, then find the range of `y`.

If (x)/(y)+(y)/(x)=-1 , where x,y ne 0 then the value of (x^3-y^3) is

Let (dy)/(dx)=(6)/(x+y) where y(0)=0 then the value of y when x+y=6 is

Solve (2)/(x) + (3)/(y) = 13, (5)/(x) - ( 4)/(y) = - 2 , where x ne 0 and y ne 0 .

If x^(y)=x^2 , then y=6.(x ne 0, x ne 1) .

Find the point on the curve y=sqrt (x-3) , where the tangent is perpendicular to the line 6x+3y-5 = 0

If the median and range of four numbers {x,y,2x+y,x−y}, where 0 lt y lt x lt 2y , are 10 and 28 respectively, then the mean of the numbers is :