[" In a YDSE: "D=1m,d=1mm" and "lambda=5000nm.],[" The distance of "1000^(" th ")" maxima from the central "],[" maxima is: "]

In YDSE, D = 1 m, d = 1 mm , and lambda = 5000 nm . The distance of the 100th maxima from the central maxima is

In YDSE, D = 1 m, d = 1 mm , and lambda = 5000 nm . The distance of the 100th maxima from the central maxima is

In a YDSE, distance between the slits and the screen is 1m, separation between the slits is 1mm and the wavelength of the light used is 5000nm . The distance of 100^(th) maxima from the central maxima is:

In a YDSE, distance between the slits and the screen is 1m, separation between the slits is 1mm and the wavelength of the light used is 5000nm . The distance of 100^(th) maxima from the central maxima is:

In a YDSE, D = 1m, d = 1mm and lambda = 1//2 mm Find a distance between the first and central maxima on the screen.

In a YDSE, D = 1 M, d = 1 mm, and lambda = 1//2 mm. (a) Find the distance between the first and central maxima on the screen. (b) Find the number of maxima and minima obtained on the screen.

In a YDSE, D = 1 M, d = 1 mm, and lambda = 1//2 mm. (a) Find the distance between the first and central maxima on the screen. (b) Find the number of maxima and minima obtained on the screen.

In a YDSE, D = 1m, d = 1mm and lambda = 1//2 mm Find the no of maxima and minima obtained on the screen.

In YDSE a = 2mm , D = 2m, lambda = 500 mm. Find distance of point on screen from central maxima where intensity becomes 50% of central maxima

In YDSE a = 2mm , D = 2m, lambda = 500 mm. Find distance of point on screen from central maxima where intensity becomes 50% of central maxima