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A stone is thrown in a vertically upward...

A stone is thrown in a vertically upward direction with a velocity of 5m/s. If the acceleration of the stone during its motion is `10 m//s^(2)` in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?

Text Solution

Verified by Experts

`V^(2)=u^(2)+2as`
`thereforeS=(v^(2)-u^(2))/(2a)=(0.(5)^(2))/(2xx(-10))`
=1.25 M
V=u+at
`t=(v-u)/a=(0-5)/(-10)=0.5 sec
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