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A car accelerates uniformly from 18 km h...

A car accelerates uniformly from 18 km `h^(-1)` to 36 km `h^(-1)` in 5s. Calculate
the distance covered by the car in that time.

Text Solution

Verified by Experts

We are given that
`u=18km^(-1)=5ms^(-1)`
`v=36kmh^(-1)=10ms^(-1)`
`t=5s`
From Eq. we have
`s=ut+1/2at^(2)`
`=5ms^(-1)xx5s+1/2xx1ms^(-2)xx(5s)^(2)`
=25m+12.5m
= 37.5 m
The ·acceleration of the car is in `ms^(-2)` and me distance covered is 37. 5 m.
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