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A stone is thrown vertically upward with...

A stone is thrown vertically upward with an initial velocity of 40 m/s. Taking g = 10 m/`s^(2)`, find the maximum height reached by the the stone. What is the net displacement and the total distance covered by the stone?

Text Solution

Verified by Experts

h = s
`v^(2) - u^(2) = `2gs
`0^(2) - (40)^(2) = 2 xx (-10) `s
s = 80 m
Total distance = 80 m + 80 m
= 160 m
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