The kinetic energy of an object of mass in moving with a velocity of `5ms^(-1)` is 25 J. What will be its kinetic energy when its velocity is doubled? What will be its kinetic energy when its velocity is increased three times?

Explanation

K.E. = 25 joules
V = 5 m/s
`KE=(1)/(2)mv^(2)`
`=m (2KE)/(mv^(2))=(2xx25)/(5)=2kg`
Kinetic energy when its velocity is doubled.
V = 10 m/s
`=(1)/(2) mv^(2)`
`=(1)/(2) xx 2xx10^(2)=100J`
Kinetic energy when its velocity is increased by three times.
`=(1)/(2)mv^(2)`
`=(1)/(2) xx 2xx15^(2)`
`=225` joules