Redraw the circuit of question 1, putting in an ammeter to measure the current through the resistors and a voltmeter to measure potential difference across the 12 `Omega` resistor. What would be the readings in the ammeter and the voltmeter?

Explanation

An ammeter should be connected in the circuit in series with , the resistors. To measure the potential difference across the resistor it should be connected in parallel, as shown in the following figure .

The resistances are connected in series. Ohm.s law can be used to obtain the readings of ammeter and voltmeter
According to Ohm.s law,
V=IR, where, Potential difference
V=6V
Current flowing through the ciruit/ resistors=I
Resistance of the circuit,
`R=5+8+12=25Omega`
`I=V//R=6//25=0.24`
A potential difference across `12Omega` resistor`=V_1` current flowing through the `12Omega` resistor, I=0.24 A
`V_1=IR=0.24xx12=2.88V`
Therefore, the reading of the ammeter will be 0.24A. The reading of the voltmeter will be 2.88V