How many `176Omega` resistors (in parallel) are required to carry 5A on a 220 V line ?

Explanation

For x number of resistor of resistance `176Omega` the equivalent resistance of the resistors connected in parallel is given by
Ohm.s law as V=IR
R=V/I
Where, Supply voltage V=220V
current, I=5A
Equivalent resistance of the combination=R, given as
`1/R=x xx(1/(176))`
`R=(176)/x`
From ohm.s law
`V/I=(176)/x`
`x=(176xx1)/(V)=(176xx5)/(220)=4`
There four resistors of `176Omega` are required to draw the given amount of current