An object 5 cm in length is held 25 cm away a converging lens of focal length 10 cm. Draw the ray diagram and find the position, size and nature of the image formed.

Explanation

Height of the Object, `h_0=5cm`
Distance of the object from converging lens, u-25cm
Focal length of converging lens, f=10cm
Using lens formula
`1/v-1/u=1/f`
`1/v=1/f+1/u=1/(10)-1/(25)=(15)/(250)`
`v=(250)/(15)=16.66cm`
Also, for a converging lens, `(h_1)/(h_0)=v/u`
`h_i=v/uxxh_0(50x5)/(3x(-25))=(10)/(-3)=-3.3cm`
Thus, the image is inverted and formed at a distance of 16. 7 cm behind the lens
and measures 3.3 cm. The ray diagram is shown below.