[Lt,(3|x|+x)/(7|x|-5x)=],[x rarr0," は "]

Lt(x rarr0)((|x|)/(x)+x+2)=

lim_(x rarr0)[sin x]

lim_(x rarr0)(|x|)/(x)

lim_(x rarr0)[cos x]is

If l = underset( x rarr 0) ("Lim")( x ( 1+ a cos x ) - bsin x ) /( x^(3))= underset( x rarr 0 ) ("Lim") ( 1+a cos x ) /( x^(2))- underset( x rarr 0 ) ("lim")( b sin x )/( x^(3)) , where l in R , then

Let lim_(x rarr0)(f(x))/(x)=1 and lim_(x rarr0)(x(1+p cos x)-q sin x)/((f(x))^(3))=1 then

Lt_(x rarr0)(x-sin x)/(x^(3))

Lt_(x rarr0)(tan^(-1)x)/(x)

lim_(x rarr 0) (|x|)/x is :