" 2."(dy)/(dx)=y+int_(0)^(1)ydx" given "y=1," where "x=0

If the solution of differential equation (dy)/(dx)=y+int_(0)^(1)ydx, given y=1 when x=0 is y=(1)/(3-e)(Ae^(x)+Be+1) then find the value of A+B.

Solve the differential equation (dy)/(dx) = y + int_(0)^(1)y(x)dx , given that the value of y is 1, when x = 0.

Solve the differential equation (dy)/(dx) = y + int_(0)^(1)y(x)dx , given that the value of y is 1 , when x = 0 .

int_(0)^(1)ydx where x=cos2y

Let a function y=f(x) satisfies the following conditions : 1.(dy)/(dx)=y+int_(0)^(1)ydx2.f(0)=1 then equal to f'(0)

int_(0)^(1)y dx where x=cos2y

(dy)/(dx)=ysin2x given, y(0)=1

Solve (x-y)(dx+dy)=dx-dy , given that y=-1 , where x=0 .

Solve (x-y)(dx+dy)=dx-dy , given that y=-1 , where x=0 .