Equation of a tangent to the curve yco...

Equation of a tangent to the curve `ycotx=y^3tanx` at the point where the abscissa is `pi/4` is (a) `4x+2y=\ pi+2` (b) `4x-2y=pi+2` (c) `x=0` (d) `y=0`

Similar Questions

Explore conceptually related problems

The equation of tangent to the curve y=2cos x at x=(pi)/4 is

The equation of tangent to the curve y=2 sinx at x=pi/4 is

Find the equation of the normal to the curve x^2+2y^2-4x-6y+8=0 at the point whose abscissa is 2.

Find the equation of the normal to the curve x^(2)+2y^(2)-4x-6y+8=0 at the point whose abscissa is 2 .

The tangent to the curve y=2+bx+3x^(2) at the point where the curve meets y-axis has the equation 4x-y+2=0 then b is

Find the equation of the tangent line to the curve y=(3x^2-1)/x at the point (1,2) is (a) 4x-y-1=0 (b) 4x+y+2=0 (c)x-y-1=0 (d) 4x-y-2=0

The equation of the normal to the curve x=a\ cos^3theta,\ \ y=a\ sin^3theta at the point theta=pi//4 is (a) x=0 (b) y=0 (c) x=y (d) x+y=a