" If dissociation for reaction,"PCl_(s)rightleftarrows PCl_(1)+Cl_(2)" is "20%" at "1" atm pressure,calculate "kappa_(C)

If dissociation for reaction, PC1_(5)hArrPC1_(3) + C1_(2) is 20% at 1 atm pressure. Calculate K_(c) .

Show that degree of dissociation (alpha) for the dissociation of PCl_(5) " into " PCl_(3)" and " Cl_(2) at pressure P is given by alpha = [(kp)/(P+ kp)]^(1//2)

The degree of dissociation of PCl_(5) (alpha) obeying the equilibrium, PCl_(5)hArrPCl_(3)+Cl_(2) is related to the pressure at equilibrium by :

The degree of dissociation of PCl_(5) (alpha) obeying the equilibrium, PCl_(5)hArrPCl_(3)+Cl_(2) is related to the pressure at equilibrium by :