The percentage by volume of `C_(3)H_(8)` in a gaseous mixture of `C_(3)H_(8),CH_(4)` and `CO` is 20. When `100mL` of the mixture is burnt in excess of `O_(2)` the volume of `CO_(2)` produced is :

The percentage by volume of C_(3)H_(8) in a gaseous mixture of C_(3)H_(8),CH_(4)andCO is 20. When 10 ml of the mixture is burnt in excess of O_(2) , the volume of CO_(2) produced is 2xml . Find the value of .x..

The % by volume of C_(4)H_(10) in a gaseous mixture of C_(4)H_(10) and CO is 40. When 200ml of the mixture is burnt in excess of O_(2) . Find volume (in ml) of CO_(2) produced.

The % by volume of C_(4)H_(10) in a gaseous mixture of C_(4)H_(10) and CO is 40. When 200ml of the mixture is burnt in excess of O_(2) . Find volume (in ml) of CO_(2) produced.

The % by volume of C_(4)H_(10) in a gaseous mixture of C_(4)H_(10) and CO is 40. When 200ml of the mixture is burnt in excess of O_(2) . Find volume (in ml) of CO_(2) produced.

The percentage by volume of C_3H_8 in a mixture of C_3H_8, CH_4 and CO is 36.5 . Calculate the volume of CO_2 produced when 100 ml of the mixture is burnt in excess of O_2 .

280 g of a mixture containing CH_(4) and C_(2)H_(6) in 5:2 molar ratio is burnt in presence of excess of oxygen. Calculate total moles of CO_(2) produced.

280 g of a mixture containing CH_(4) and C_(2)H_(6) in 5:2 molar ratio is burnt in presence of excess of oxygen. Calculate total moles of CO_(2) produced.