A body of mass `M` is resting on a rough horizontal plane surface the coefficient of friction being equal to `mu` At `t = 0` a horizontal force `F = F_(0) t` starts acting on it , where `F_(0)` is a constant find the time T at which the motion starts?

A body of mass M rests on a horizontal plane having coefficient of friction mu . At t=0 a horizontal force vec(F) is applied that varies with time vec(F)(t)=vec(F)_(0) t where vec(F)_(0) is a constant vector. The time instant t_(0) at which motion starts and distance moved in t second will be:

A body of mass 2 kg is kept on a rough horizontal surface as shown in the figure. If coefficient of friction is 0.5, find the work done by frictional force in the interval t=0 to t=5 sec

A block is kept on a rough horizontal surface as shown. Its mass is 2 kg and coefficient of friction between block and surface (mu)=0.5. A horizontal force F is acting on the block. When

A block is kept on a rough horizontal surface as shown. Its mass is 2 kg and coefficient of friction between block and surface (mu)=0.5. A horizontal force F is acting on the block. When

A block is kept on a rough horizontal surface as shown. Its mass is 2 kg and coefficient of friction between block and surface (mu)=0.5. A horizontal force F is acting on the block. When

A bar of mass m_(1) is placed on a plank of mass m_(2) which rests on a smooth horizontal plane . The coefficient of friction between the surfaces of bar and plank is k . The plank is subjected to a horizontal force F depending on time t as F = at , where a is a constant . The moment of time t_(0) at which the plank starts sliding is :