What is the oxidation number of the metals `[Fe(CN)_6]^(4-)`

Explanation

Fe in `[Fe(CN)_6]^(4-)` . Let the oxidation number of Fe in `[Fe(CN)_6]^(4-)` be x and CN be -1
i.e., `oversetx(Fe)overset(-)((CN))_6`
`therefore` Sum of oxidation number of all the atoms in `[Fe(CN)_6]^(4-)=x+6(-1)=-4,x-6=-4,x=+2`
Thus, the oxidation number of Fe in `[Fe(CN)_6]^(4-)` is +2.