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What is the oxidation number of sulphur ...

What is the oxidation number of sulphur in the following molecules/ ions
`SO_4^(2-)`

Text Solution

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In `SO_4^(2-)` Let x be oxidation number of S, Oxidation number of Oxygen is -2.
`S O_4^(2-)`
Let oxidation number be x -2 `therefore (1 times x)+ (4 times -2)=-2 implies x-8=-2 implies x=-2+8 implies x=6` Oxidation number of S in `SO_4^(2-)` is +6.
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Knowledge Check

  • The oxidation number and covalency of sulphur in S_8 molecule are

    A
    1,3
    B
    2,4
    C
    0,2
    D
    2,0

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