What is the oxidation number of sulphur in the following molecules/ ions
`SO_4^(2-)`

Explanation

In `SO_4^(2-)` Let x be oxidation number of S, Oxidation number of Oxygen is -2.
`S O_4^(2-)`
Let oxidation number be x -2 `therefore (1 times x)+ (4 times -2)=-2 implies x-8=-2 implies x=-2+8 implies x=6` Oxidation number of S in `SO_4^(2-)` is +6.