What is the oxidation number of sulphur in the following molecules/ ions
`H_2SO_4`

Explanation

In `H_2SO_4` let x,+1 ,-2 be oxidation number of S, H and O
Let ON Be

i.e., `(+1 times 2)+ (x times 1)+(-2 times 4)=0`
`implies (1 times 2)+x+ (-2 times 4) =0 , 2+ x-8=0, x=+6`
Oxidation number of S in `H_2SO_4` is +6.