The equilibrium constant for the reactio...

The equilibrium constant for the reaction is 10. Calculate the value of `DeltaG^(@)`, Given `R=8.314JK^(-1)"mol"^(-1)T=300K`

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The ratio of rate constants of a reaction at 300K and 291K is 2. Calculate the energy of activation. ("Given "R = "8.314JK"^(-1)" mol"^(-1)) .

The equilibrium constant for a reaction is 10. Delta G^(theta) will be R = 8 JK^(-1) mol^(-1) , T = 300 K)

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a) The rate of a particular reaction doubles when the temperature changes from 300 K to 310 K. Calculate the energy of activation of the reaction. [Given : R="8.314 JK"^(-1)" mol"^(-1) ].

Show that R=8.314 Jmol^(-1)K^(-1)

If equilibrium constant K is 10^(3) , the Delta G^(theta) for the reaction at 300 K is (assume R = 8.314 JK^(-1) mol^(-1) ) :

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