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5.8 g of non - volatile, non - electroly...

5.8 g of non - volatile, non - electrolyte solute was dissolved in 100 g of carbon disuiphide `(CS_(2))`. The vapour pressure of the solution was found to be 190 mm of Hg. Calculate molar mass of the solute. Given : Vapour of pure `CS_(2)` is 195 mm of Hg and molar mass of `CS_(2)` is `76g//mol`.

Text Solution

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Given: Vapour pressure of pure CS is 195 mm of Hg and molar mass of `CS_(2) is 76g//mol`
`:. M_(2) = w_(2)M_(1)/w_(1) (P^(0)/P^(0)-P) = 5.8 xx 76/100 (195/195-100) = 5.8 xx 76 xx 195/ 500`
`:. M_(2) = 171.91 g mol^(-1)`
(b) Ideal solution:
• Obeys Raoult.s law
•`DeltaV_(mix) = 0`
•`DeltaH_(mix) = 0`
Non-Ideal solution:
• Does not obey Raoult.s law
•`DeltaV_(mix) != 0`
•`DeltaH_(mix) != 0`
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