Home
Class 12
CHEMISTRY
Explain the hybridisation, geometry and ...

Explain the hybridisation, geometry and magnetic property of `[Ni(Cl)_(4)]^(2-)`.

Text Solution

Verified by Experts

(i) Orbitals of `Ni^(2+)` ion
(ii) In presence of strong ligand `CN^(-)` spin pairing takes place and `dsp^(2)` hybridisation takes place.

(ii) Four pairs of electrons, one from each CN occupy the four hybrid orbitals. Thus the complex has square planar geometry and diamagnetic because of the absence of unpaired electrons.

For `[Ni(CN)_(4)]^(-2)`Complex:
(i) Type of hybridisation : `dsp^(2)`
(ii) Geometry : Square planar
(iii) Magnetic property : Diamagnetic
Promotional Banner

Topper's Solved these Questions

  • ANNUAL EXAMINATION QUESTION PAPER MARCH 2019

    SUBHASH PUBLICATION|Exercise PART D|11 Videos
  • ANNUAL EXAMINATION QUESTION PAPER MARCH 2019

    SUBHASH PUBLICATION|Exercise PART B|8 Videos
  • ANNUAL EXAMINATION QUESTION PAPER MARCH 2018

    SUBHASH PUBLICATION|Exercise PART-D|24 Videos
  • BIOMOLECULES

    SUBHASH PUBLICATION|Exercise QUESTION|77 Videos

Similar Questions

Explore conceptually related problems

Explain the hybridisation, geometry and magnetic property of [CoF_(6)]^(3-) based on VBT.

Explain the hybridisation, geometry and magnetic prpoperty of [Co(NH_(3))_(6)]^(3+) based on VBT.

With the help of Valence Bond theory account for hybridisation, geometry and magnetic property of [Ni(CN)_(4)]^(2-) complex ion [Z" for "Ni=28]

Explain the hybridization, geometry and magnetic property of [Co(NH_3)_6]^(3+) ion on the basis of Valance Bond Theory (VBT). [Atomic number of Co= 27].

On the basis of VBT explain the hybridization, geometrical shape and magnetic property of [CoF_(6)]^(3-) , hexafluorido cobaltate (III) ion.

Using VBT, explainthe geometry and magnetic property of [Ni(CN)_(4)]^(-2) . (Atomic Number of Ni=28).