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lambda(m)^(@) for NaCl, HCl and CH(3)COO...

`lambda_(m)^(@)` for `NaCl, HCl and CH_(3)COONa` are 126.4,425.9 and `"91.0 S cm"^(2)//"mol"` respectively. Calculate `lambda_(m)^(@)" for "CH_(3)COOH`.

Text Solution

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Given: `lambda_m^0(NaCl)= 126.4 Scm^2/mol` `lambda_m^0`(HCl)=425.9` Scm^2`/mol `lambda_m^0(CH_3COONa)=91.0 Scm^2`/mol `lambda_m^0(CH_3COOH)=lambda_m^0_(HCl)+lamda_m^0(CH_3COONa) -lambda_M^0(NaCl) =425.9 + 91.0 - 126.4 = 390.5 Scm^2 mol^-1`
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